Optimal. Leaf size=83 \[ \frac{1}{2} \left (a d^2+2 c\right ) \tan ^{-1}\left (\sqrt{d x-1} \sqrt{d x+1}\right )+\frac{a \sqrt{d x-1} \sqrt{d x+1}}{2 x^2}+\frac{b \sqrt{d x-1} \sqrt{d x+1}}{x} \]
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Rubi [A] time = 0.191248, antiderivative size = 129, normalized size of antiderivative = 1.55, number of steps used = 6, number of rules used = 6, integrand size = 32, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.188, Rules used = {1610, 1807, 807, 266, 63, 205} \[ \frac{\sqrt{d^2 x^2-1} \left (a d^2+2 c\right ) \tan ^{-1}\left (\sqrt{d^2 x^2-1}\right )}{2 \sqrt{d x-1} \sqrt{d x+1}}-\frac{a \left (1-d^2 x^2\right )}{2 x^2 \sqrt{d x-1} \sqrt{d x+1}}-\frac{b \left (1-d^2 x^2\right )}{x \sqrt{d x-1} \sqrt{d x+1}} \]
Antiderivative was successfully verified.
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Rule 1610
Rule 1807
Rule 807
Rule 266
Rule 63
Rule 205
Rubi steps
\begin{align*} \int \frac{a+b x+c x^2}{x^3 \sqrt{-1+d x} \sqrt{1+d x}} \, dx &=\frac{\sqrt{-1+d^2 x^2} \int \frac{a+b x+c x^2}{x^3 \sqrt{-1+d^2 x^2}} \, dx}{\sqrt{-1+d x} \sqrt{1+d x}}\\ &=-\frac{a \left (1-d^2 x^2\right )}{2 x^2 \sqrt{-1+d x} \sqrt{1+d x}}+\frac{\sqrt{-1+d^2 x^2} \int \frac{2 b+\left (2 c+a d^2\right ) x}{x^2 \sqrt{-1+d^2 x^2}} \, dx}{2 \sqrt{-1+d x} \sqrt{1+d x}}\\ &=-\frac{a \left (1-d^2 x^2\right )}{2 x^2 \sqrt{-1+d x} \sqrt{1+d x}}-\frac{b \left (1-d^2 x^2\right )}{x \sqrt{-1+d x} \sqrt{1+d x}}+\frac{\left (\left (2 c+a d^2\right ) \sqrt{-1+d^2 x^2}\right ) \int \frac{1}{x \sqrt{-1+d^2 x^2}} \, dx}{2 \sqrt{-1+d x} \sqrt{1+d x}}\\ &=-\frac{a \left (1-d^2 x^2\right )}{2 x^2 \sqrt{-1+d x} \sqrt{1+d x}}-\frac{b \left (1-d^2 x^2\right )}{x \sqrt{-1+d x} \sqrt{1+d x}}+\frac{\left (\left (2 c+a d^2\right ) \sqrt{-1+d^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{-1+d^2 x}} \, dx,x,x^2\right )}{4 \sqrt{-1+d x} \sqrt{1+d x}}\\ &=-\frac{a \left (1-d^2 x^2\right )}{2 x^2 \sqrt{-1+d x} \sqrt{1+d x}}-\frac{b \left (1-d^2 x^2\right )}{x \sqrt{-1+d x} \sqrt{1+d x}}+\frac{\left (\left (2 c+a d^2\right ) \sqrt{-1+d^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{1}{d^2}+\frac{x^2}{d^2}} \, dx,x,\sqrt{-1+d^2 x^2}\right )}{2 d^2 \sqrt{-1+d x} \sqrt{1+d x}}\\ &=-\frac{a \left (1-d^2 x^2\right )}{2 x^2 \sqrt{-1+d x} \sqrt{1+d x}}-\frac{b \left (1-d^2 x^2\right )}{x \sqrt{-1+d x} \sqrt{1+d x}}+\frac{\left (2 c+a d^2\right ) \sqrt{-1+d^2 x^2} \tan ^{-1}\left (\sqrt{-1+d^2 x^2}\right )}{2 \sqrt{-1+d x} \sqrt{1+d x}}\\ \end{align*}
Mathematica [A] time = 0.116759, size = 82, normalized size = 0.99 \[ \frac{\left (d^2 x^2-1\right ) (a+2 b x)+x^2 \sqrt{d^2 x^2-1} \left (a d^2+2 c\right ) \tan ^{-1}\left (\sqrt{d^2 x^2-1}\right )}{2 x^2 \sqrt{d x-1} \sqrt{d x+1}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0., size = 103, normalized size = 1.2 \begin{align*} -{\frac{ \left ({\it csgn} \left ( d \right ) \right ) ^{2}}{2\,{x}^{2}}\sqrt{dx-1}\sqrt{dx+1} \left ( \arctan \left ({\frac{1}{\sqrt{{d}^{2}{x}^{2}-1}}} \right ){x}^{2}a{d}^{2}+2\,\arctan \left ({\frac{1}{\sqrt{{d}^{2}{x}^{2}-1}}} \right ){x}^{2}c-2\,\sqrt{{d}^{2}{x}^{2}-1}xb-\sqrt{{d}^{2}{x}^{2}-1}a \right ){\frac{1}{\sqrt{{d}^{2}{x}^{2}-1}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 4.01953, size = 88, normalized size = 1.06 \begin{align*} -\frac{1}{2} \, a d^{2} \arcsin \left (\frac{1}{\sqrt{d^{2}}{\left | x \right |}}\right ) - c \arcsin \left (\frac{1}{\sqrt{d^{2}}{\left | x \right |}}\right ) + \frac{\sqrt{d^{2} x^{2} - 1} b}{x} + \frac{\sqrt{d^{2} x^{2} - 1} a}{2 \, x^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.17296, size = 173, normalized size = 2.08 \begin{align*} \frac{2 \, b d x^{2} + 2 \,{\left (a d^{2} + 2 \, c\right )} x^{2} \arctan \left (-d x + \sqrt{d x + 1} \sqrt{d x - 1}\right ) +{\left (2 \, b x + a\right )} \sqrt{d x + 1} \sqrt{d x - 1}}{2 \, x^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 33.6278, size = 212, normalized size = 2.55 \begin{align*} - \frac{a d^{2}{G_{6, 6}^{5, 3}\left (\begin{matrix} \frac{7}{4}, \frac{9}{4}, 1 & 2, 2, \frac{5}{2} \\\frac{3}{2}, \frac{7}{4}, 2, \frac{9}{4}, \frac{5}{2} & 0 \end{matrix} \middle |{\frac{1}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac{3}{2}}} + \frac{i a d^{2}{G_{6, 6}^{2, 6}\left (\begin{matrix} 1, \frac{5}{4}, \frac{3}{2}, \frac{7}{4}, 2, 1 & \\\frac{5}{4}, \frac{7}{4} & 1, \frac{3}{2}, \frac{3}{2}, 0 \end{matrix} \middle |{\frac{e^{2 i \pi }}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac{3}{2}}} - \frac{b d{G_{6, 6}^{5, 3}\left (\begin{matrix} \frac{5}{4}, \frac{7}{4}, 1 & \frac{3}{2}, \frac{3}{2}, 2 \\1, \frac{5}{4}, \frac{3}{2}, \frac{7}{4}, 2 & 0 \end{matrix} \middle |{\frac{1}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac{3}{2}}} - \frac{i b d{G_{6, 6}^{2, 6}\left (\begin{matrix} \frac{1}{2}, \frac{3}{4}, 1, \frac{5}{4}, \frac{3}{2}, 1 & \\\frac{3}{4}, \frac{5}{4} & \frac{1}{2}, 1, 1, 0 \end{matrix} \middle |{\frac{e^{2 i \pi }}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac{3}{2}}} - \frac{c{G_{6, 6}^{5, 3}\left (\begin{matrix} \frac{3}{4}, \frac{5}{4}, 1 & 1, 1, \frac{3}{2} \\\frac{1}{2}, \frac{3}{4}, 1, \frac{5}{4}, \frac{3}{2} & 0 \end{matrix} \middle |{\frac{1}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac{3}{2}}} + \frac{i c{G_{6, 6}^{2, 6}\left (\begin{matrix} 0, \frac{1}{4}, \frac{1}{2}, \frac{3}{4}, 1, 1 & \\\frac{1}{4}, \frac{3}{4} & 0, \frac{1}{2}, \frac{1}{2}, 0 \end{matrix} \middle |{\frac{e^{2 i \pi }}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac{3}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.98699, size = 196, normalized size = 2.36 \begin{align*} -\frac{{\left (a d^{3} + 2 \, c d\right )} \arctan \left (\frac{1}{2} \,{\left (\sqrt{d x + 1} - \sqrt{d x - 1}\right )}^{2}\right ) + \frac{2 \,{\left (a d^{3}{\left (\sqrt{d x + 1} - \sqrt{d x - 1}\right )}^{6} - 4 \, b d^{2}{\left (\sqrt{d x + 1} - \sqrt{d x - 1}\right )}^{4} - 4 \, a d^{3}{\left (\sqrt{d x + 1} - \sqrt{d x - 1}\right )}^{2} - 16 \, b d^{2}\right )}}{{\left ({\left (\sqrt{d x + 1} - \sqrt{d x - 1}\right )}^{4} + 4\right )}^{2}}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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